(2x-3)x^2+2x+(x-1)=0

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Solution for (2x-3)x^2+2x+(x-1)=0 equation: 


Simplifying
(2x + -3) * x2 + 2x + (x + -1) = 0

Reorder the terms:
(-3 + 2x) * x2 + 2x + (x + -1) = 0

Reorder the terms for easier multiplication:
x2(-3 + 2x) + 2x + (x + -1) = 0
(-3 * x2 + 2x * x2) + 2x + (x + -1) = 0
(-3x2 + 2x3) + 2x + (x + -1) = 0

Reorder the terms:
-3x2 + 2x3 + 2x + (-1 + x) = 0

Remove parenthesis around (-1 + x)
-3x2 + 2x3 + 2x + -1 + x = 0

Reorder the terms:
-1 + 2x + x + -3x2 + 2x3 = 0

Combine like terms: 2x + x = 3x
-1 + 3x + -3x2 + 2x3 = 0

Solving
-1 + 3x + -3x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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